+0  
 
0
132
9
avatar+733 

Evaluate each without using a calculator.

1) \(sin(\frac{\pi}{3})\)

2) \(cos(\frac{\pi}{4})\)

3) \(tan(\frac{\pi}{4})\)

4) \(csc(\frac{\pi}{3})\)

5) \(sec(\frac{\pi}{3})\)

6) \(cot(\frac{\pi}{6})\)

AdamTaurus  Jan 16, 2018
Sort: 

9+0 Answers

 #1
avatar+82944 
+2

sin (pi/3)  =  √3/2

cos(pi/4) =  √2/2

tan (pi/4)   =  1

csc(pi/3)  =  2/√3  =  2√3 / 3

sec (pi/3)  =  1 / cos(pi/3) =  1 / (1/2)  =   2

cot (pi/6)  =  1 / tan (pi/6)  =  1 / (1/√3)  =   √3

 

 

 

cool cool cool

CPhill  Jan 17, 2018
 #2
avatar+733 
+2

Can you show me the process of how you did at least one of them? Like, how did you jump from sin(pi/3) to √3/2?

AdamTaurus  Jan 17, 2018
 #3
avatar+82944 
+1

These are common reference angles,  Adam

 

You really just need to memorize this chart :

 

http://www.analyzemath.com/trigonometry/special_angles.html

 

Note that the reciprocal  of  √2/2  = 2 / √2  =  √2*√2 / √ 2 =  √2

 

It's not as bad as it looks...since  csc, sec and cot  are just reciprocals of sin, cos and tan, respectively.....just learn the values for sin, cos and tan......"flip" these over for  csc, sec and tan!!!

 

This is the way I  had to learn them.....sad sad sad

CPhill  Jan 17, 2018
 #4
avatar+6365 
+2

To find  sin( pi/3 ) ,  we can start with an equilateral triangle with side length  1 .

 

 

Now draw a line that bisects an angle and the opposite side. The length of this line is sin(pi/3) .

 

 

By the Pythagorean theorem...

 

(1/2)2  +  ( sin(pi/3) )2   =   12

                                                       Subtract  (1/2)2  from both sides of the equation.

( sin(pi/3) )2   =   12  -  (1/2)2

                                                       Take the positive sqrt of both sides.

sin(pi/3)   =   √[12  -  (1/2)2]

 

sin(pi/3)   =   √[1  -  1/4]

 

sin(pi/3)   =   √[3/4]

 

sin(pi/3)   =   √3 / 2       smiley

hectictar  Jan 17, 2018
 #5
avatar+733 
+2

Geez, that was an extremely detailed answer. Thanks, Hectictar! I've learned an easier way to do it though.

First I convert radians to degrees.

\(\frac{\pi}{3}*(\frac{180^o}{\pi})\)

Multiply.

\(\frac{\pi*180^o}{3\pi}\)

The pi cancels.

\(\frac{180^o}{3}=60^o\)

So it is sin(60o), and since I know the values of sin, cos, and tan of 30o, 45o, and 60o, I know that \(sin(60^o)=\frac{\sqrt{3}}{2}\).

AdamTaurus  Jan 18, 2018
 #6
avatar+6365 
0

How do you know the value of sin( 60° )   ?  smiley

hectictar  Jan 18, 2018
 #7
avatar+1720 
+2

This method works for anyone, assuming you have five fingers on your hand. This could b**w your mind, literally! This will allow you to know the sin of the following numbers listed on each finger. Keep your hat on, if you have one! Attempt to hold back knocking your socks off!

 

 

Lay your hand out like so! Now, let's say you want to know the value of \(\sin60\). Here is our magic formula. \(\sin x=\frac{\sqrt{\text{# of fingers to the left of finger x}}}{2}\). In this case, finger x is 60. The number of fingers to the left is 3, so \(\sin60=\frac{\sqrt{3}}{2}\). Magic, right? I think so! 

 

Wait, don't leave yet! Your fingers can also do the other trigonometric function: cosine! Don't believe me? Well, it is simple, too! Don't fret. Let's find the \(\cos60\). The formula now is \(\cos x=\frac{\sqrt{\text{# of fingers to the right of finger x}}}{2}\). There is 1 finger to the left of finger 60, so \(\cos 60=\frac{\sqrt{1}}{2}=\frac{1}{2}\). Try it out with other values on the hand! 

 

What about tangent? Well, this is where the magic ends, unfortunately. The only thing I can suggest is that \(\tan x=\frac{\sin x}{\cos x}\), which you can get those values using the finger trick already learned! Have fun defeating those trigonometric headaches.

TheXSquaredFactor  Jan 22, 2018
 #8
avatar+91797 
+1

Hi    TheXSquaredFactor,

 

That is really cool.  I have never seen that trick before! 

Melody  Jan 22, 2018
 #9
avatar+733 
+1

I've had to memorize the values of sin, cos, and tan of angles 30o, 45o, and 60o.

AdamTaurus  Jan 23, 2018

13 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details