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slope-intercept is y=mx+b. How would you put (0,1) and (-3,-2) in the equation?

 Oct 17, 2017

Best Answer 

 #1
avatar+7348 
+1

m  =  slope  =  \(\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-1}{-3-0}\,=\,\frac{-3}{-3}\,=\,1\)

 

Using the point  (0, 1), the equation in point-slope form is

 

y - 1  =  1(x - 0)      Simplify

y - 1  =  x               Add  1  to both sides.

y  =  x + 1              This is the equation in  y = mx + b  form.

 Oct 17, 2017
 #1
avatar+7348 
+1
Best Answer

m  =  slope  =  \(\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-1}{-3-0}\,=\,\frac{-3}{-3}\,=\,1\)

 

Using the point  (0, 1), the equation in point-slope form is

 

y - 1  =  1(x - 0)      Simplify

y - 1  =  x               Add  1  to both sides.

y  =  x + 1              This is the equation in  y = mx + b  form.

hectictar Oct 17, 2017

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