+0

# slope-intercept is y=mx+b. How would you put (0,1) and (-3,-2) in the equation?

0
136
1

slope-intercept is y=mx+b. How would you put (0,1) and (-3,-2) in the equation?

Guest Oct 17, 2017

#1
+6961
+1

m  =  slope  =  $$\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-1}{-3-0}\,=\,\frac{-3}{-3}\,=\,1$$

Using the point  (0, 1), the equation in point-slope form is

y - 1  =  1(x - 0)      Simplify

y - 1  =  x               Add  1  to both sides.

y  =  x + 1              This is the equation in  y = mx + b  form.

hectictar  Oct 17, 2017
Sort:

#1
+6961
+1

m  =  slope  =  $$\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-1}{-3-0}\,=\,\frac{-3}{-3}\,=\,1$$

Using the point  (0, 1), the equation in point-slope form is

y - 1  =  1(x - 0)      Simplify

y - 1  =  x               Add  1  to both sides.

y  =  x + 1              This is the equation in  y = mx + b  form.

hectictar  Oct 17, 2017

### 27 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details