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1.passes through (-6,-1) and parallel to x-y=4

2. passes thorugh (-1,-8) and perpendicular to x+3y=-6

write the equation of the line in slope intercept form.

 Jun 8, 2020
edited by xxJenny1213xx  Jun 8, 2020
 #1
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1.  Rewrite the equation in the form:  y = x - 4  This has slope m = 1, so any line parallel to it will have the same slope, so it will look like y = x + k where k is a constant.  To find k, use the fact that it goes through point (-6, -1). i.e.  you get k from:  -1 = 1*(-6) + k.

 

2.   Rewrite the equation in the form:  y = -x/3 - 2.  This has slope m = -1/3.  Any line perpendicular to this has slope equal to -1/m.  Again get the constant by substituting the specified point value to the perpendicular equation  y = (-1/m)*x + k.

 Jun 9, 2020
 #2
avatar+318 
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thank you!

xxJenny1213xx  Jun 9, 2020

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