+73 Wheelchair ramps for access to public buildings are allowed a maximum of one inch of vertical increase for every one foot of horizontal distance. Would a ramp that is 10 feet long and 8 inches tall meet this guideline? Explain your reasoning to a classmate.
+37146 10 feet is the length ....it is also the HYPOTENUSE of a right triangle.
ONE leg is 8 inches, or 2/3 ft
we need to fing the OTHER LEG
a^2 +b^2 = c^2 Pythagorean Theorem
(2/3)^2 + b^2 = 10^2
b^2 = 100 - 2/3^2
b=9.9777 ft
SO the horizontal distance is 9.9777feet and the rise can be (according to guidelines) 9.9777 inches or less so this ramp is OK !
A little calculation error on the last step.....corrected it....the ramp is still OK
+37146 10 feet is the length ....it is also the HYPOTENUSE of a right triangle.
ONE leg is 8 inches, or 2/3 ft
we need to fing the OTHER LEG
a^2 +b^2 = c^2 Pythagorean Theorem
(2/3)^2 + b^2 = 10^2
b^2 = 100 - 2/3^2
b=9.9888 ft
SO the horizontal distance is 9.9888 feet and the rise can be (according to guidelines) 9.9888 inches or less so this ramp is OK !
+37146 10 feet is the length ....it is also the HYPOTENUSE of a right triangle.
ONE leg is 8 inches, or 2/3 ft
we need to fing the OTHER LEG
a^2 +b^2 = c^2 Pythagorean Theorem
(2/3)^2 + b^2 = 10^2
b^2 = 100 - 2/3^2
b=9.9777 ft
SO the horizontal distance is 9.9777feet and the rise can be (according to guidelines) 9.9777 inches or less so this ramp is OK !
A little calculation error on the last step.....corrected it....the ramp is still OK
