y = 3x + 10
3x + 2y = 16
Since y = 3x + 10 we can replace y with 3x + 10
3x + 2(3x + 10) = 16
Distribute 2 to the terms in parenthesees
3x + 6x + 20 = 16
Combine 3x and 6x to get 9x
9x + 20 = 16
Subtract 20 from both sides of the equation
9x = -4
Divide both sides of the equation by 9
x = -4/9
Now that we know x we can plug this back into the first equation to find y
y = 3x + 10 = 3(-4/9) + 10 = -4/3 + 10 = 26/3
So the solution to the system of equations is (-4/9, 26/3)
y = 3x + 10
3x + 2y = 16
Since y = 3x + 10 we can replace y with 3x + 10
3x + 2(3x + 10) = 16
Distribute 2 to the terms in parenthesees
3x + 6x + 20 = 16
Combine 3x and 6x to get 9x
9x + 20 = 16
Subtract 20 from both sides of the equation
9x = -4
Divide both sides of the equation by 9
x = -4/9
Now that we know x we can plug this back into the first equation to find y
y = 3x + 10 = 3(-4/9) + 10 = -4/3 + 10 = 26/3
So the solution to the system of equations is (-4/9, 26/3)