So I have two triangles here... but are they overlapping? I can't draw I diagram that fits the discription :P Does anyone have a sugestion? :)
Here's a pic of what's going on, Rose98:
And DE is a perpendicular bisector to BC, so BE = CE. And angle CED = angle BED, because a perpendicular forms equal right angles. And DE = DE. So, by SAS, triangle BDE is congruent to triangle CDE.
So, m< BED = 90. And since BDE and CDE are congruent triangles, then angle BDE = angle CDE. But BDE and CDE are equal angles of the right angle BDC....thus, they = 45 degrees. And angle DBE is the remaining angle in triangle BDE, so it must be 45 degrees.
And there you go.......
I'm at a library, rosala, and this computer is acting rather odd....I told Rose98 that I would do a better job when I got home and could use my trusty laptop !!!!