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So I have two triangles here... but are they overlapping? I can't draw I diagram that fits the discription :P  Does anyone have a sugestion? :) 

Rose98  Jul 12, 2014

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 #4
avatar+11753 
+5

oh okay!but i just saw u had written a whole answer for it!And u could add a diagram or pic to the answer when u get back home!That answer wasnt that bad!But as your wish , i was just asking!

rosala  Jul 12, 2014
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 #1
avatar+78739 
+5

Here's a pic of what's going on, Rose98:

Note that

And DE is a perpendicular bisector to BC, so BE  = CE.  And angle CED = angle BED, because a perpendicular forms equal right angles. And DE = DE. So, by SAS, triangle BDE is congruent to triangle CDE.

So, m< BED = 90. And since BDE and CDE are congruent triangles, then angle BDE = angle CDE. But BDE and CDE are equal angles of the right angle BDC....thus, they = 45 degrees. And angle DBE is the remaining angle in triangle BDE, so it must be 45 degrees.

And there you go.......

 

CPhill  Jul 12, 2014
 #2
avatar+11753 
0

CPhill why did u deleted the whole bog answer you wrote!

rosala  Jul 12, 2014
 #3
avatar+78739 
0

I'm at a library, rosala, and this computer is acting rather odd....I told Rose98 that I would do a better job when I got home and could use my trusty laptop !!!!

 

  

CPhill  Jul 12, 2014
 #4
avatar+11753 
+5
Best Answer

oh okay!but i just saw u had written a whole answer for it!And u could add a diagram or pic to the answer when u get back home!That answer wasnt that bad!But as your wish , i was just asking!

rosala  Jul 12, 2014

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