The volume of the apple juice in a glass whose shape is an inverted frustum of a cone is 1176π mm³. The depth of the juice is 18mm.
Find the radius of the lower base if the product of its radii is 60 mm². *
a.5 mm
b.6 mm
c.7 mm
d.8mm
+14995 The volume of the apple juice in a glass whose shape is an inverted frustum of a cone is 1176π mm³. The depth of the juice is 18mm.
Find the radius of the lower base if the product of its radii is 60 mm². *
a.5 mm
b.6 mm
c.7 mm
d.8mm
Hello Guest!
\(V=\dfrac{1}{3}\pi h(R^2+Rr+r^2)\\ 1176mm^3=\dfrac{1}{3}\cdot 18mm\cdot (R^2+60mm^2+r^2)\\\)
\(Rr=60mm^2\\ R= \dfrac{60mm^2}{r}\)
\(1176mm^3=\dfrac{1}{3}\cdot 18mm\cdot ( (\frac{60mm^2}{r})^2+60mm^2+r^2)\)
\((\frac{60mm^2}{r})^2+60mm^2+r^2=196mm^2\\ 3600mm^4+60r^2mm^2+r^4=196r^2mm^2\\ r^2=x\)
\(3600mm^4+60x\ mm^2+x^2=196x\ mm^2\\ 3600mm^4-136x\ mm^2+x^2=0\)
\(x=68\pm \sqrt{4624-3600}\\ x=68\pm 32\\ r=\sqrt{x}\\ r=\sqrt{68-32}\)
\(r=6\ mm\)
The radius of the base of the frustum of a cone is 6mm.
b. it's right.
!
