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solve 300=22t+1.2t^2

 Sep 17, 2014

Best Answer 

 #1
avatar+129840 
+5

300=22t+1.2t^2    multiplying through by 10 to clear the decimal and rearranging, we have

12t2 + 220t -3000 = 0      divide through by 4

3t2 + 55t - 750 = 0          this can't be factored, so let's use the on-site calculator to solve it.....

$${\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{t}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{55}}{\mathtt{\,\times\,}}{\mathtt{t}}{\mathtt{\,-\,}}{\mathtt{750}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = {\mathtt{\,-\,}}{\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{481}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{55}}\right)}{{\mathtt{6}}}}\\
{\mathtt{t}} = {\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{481}}}}{\mathtt{\,-\,}}{\mathtt{55}}\right)}{{\mathtt{6}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = -{\mathtt{27.443\: \!093\: \!499\: \!551\: \!090\: \!7}}\\
{\mathtt{t}} = {\mathtt{9.109\: \!760\: \!166\: \!217\: \!757\: \!3}}\\
\end{array} \right\}$$

And there are the two solutions........

 

 Sep 17, 2014
 #1
avatar+129840 
+5
Best Answer

300=22t+1.2t^2    multiplying through by 10 to clear the decimal and rearranging, we have

12t2 + 220t -3000 = 0      divide through by 4

3t2 + 55t - 750 = 0          this can't be factored, so let's use the on-site calculator to solve it.....

$${\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{t}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{55}}{\mathtt{\,\times\,}}{\mathtt{t}}{\mathtt{\,-\,}}{\mathtt{750}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = {\mathtt{\,-\,}}{\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{481}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{55}}\right)}{{\mathtt{6}}}}\\
{\mathtt{t}} = {\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{481}}}}{\mathtt{\,-\,}}{\mathtt{55}}\right)}{{\mathtt{6}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = -{\mathtt{27.443\: \!093\: \!499\: \!551\: \!090\: \!7}}\\
{\mathtt{t}} = {\mathtt{9.109\: \!760\: \!166\: \!217\: \!757\: \!3}}\\
\end{array} \right\}$$

And there are the two solutions........

 

CPhill Sep 17, 2014

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