cot x + 6 sin x - 2 cos x =3 we can write
cosx / sinx + 6sin x - 2 cosx = 3 multiply through by sin x
cos x + 6 sin^2x - 2cosx sin x = 3sin x
cos x + 6sin^2x - 2sin cos x - 3sin x = 0 we can factor this as
( 3sinx - cosx) (2sinx - 1) = 0 set each factor to 0 and solve
3sinx - cos x = 0
3sin x = cos x
3sinx / cos x = 1
3 tan x = 1
tan x = 1/3
arctan (1/3) ≈ 18.435° + 180°n where n is an intreger
For the other factor we have that
2sinx - 1 = 0
2sin x = 1
sin x = 1/2
arcsin (1/2) and this happens at 30° + 360°n and at 150° + 360°n
And again, n is an integer
Here's ther graph : https://www.desmos.com/calculator/eiai1cs0i1
Nice CPhill !! This was harder than it first looks, for me at least ! Here is just the factoring part. I did it at first just to see it for myself, and then I figured it couldn't hurt to post it.
cos x + 6 sin2x - 2 sin x cos x - 3 sin x = 0 Rearrange.
6 sin2x - 3 sin x + cos x - 2 sin x cos x = 0 Factor out 3 sin x from the first two terms and
factor out -cos x from the last two terms.
3 sin x (2 sin x - 1) - cos x (-1 + 2 sin x) = 0 Factor out (2 sin x - 1) from both terms.
(2 sin x - 1)(3 sin x - cos x) = 0