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**Solve each equation and express your answer in simplest radical form:**

1.) 5x - 7x^2 = 3x + 4

2.) -x^2 + 4x = 13

GAMEMASTERX40 Feb 27, 2019

#1**+2 **

1. 5x - 7x^2 = 3x +4 add 7x^2 to both sides 0f the equation

5x = 7x^2 + 3x + 4 subtract 5x from both sides

0 = 7x^2 -5x +3x+4 simplify

0 = 7x^2 - 2x + 4 SInce the question states that it is 'radical form' you will need to use Quadratic Formula (rather than factoring) to find 'roots'

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a = 7 b = -2 c = 4

[ 2 +- sqrt((-2)^2 - 4(7)(4) ] / [ 2(7) ] = 2 +- sqrt(-108) / 14 = 2+- 6i sqrt(3) / 14 = 1/7 +- 3/7 i sqrt(3)

Think you can do the second one now?

2. - x^2 +4x = 13

x^2 -4x +13 = 0 a = 1 b = -4 c = 13

ElectricPavlov Feb 27, 2019

edited by
ElectricPavlov
Feb 27, 2019

edited by ElectricPavlov Feb 27, 2019

edited by ElectricPavlov Feb 27, 2019

edited by ElectricPavlov Feb 27, 2019

edited by ElectricPavlov Feb 27, 2019