Solve each equation and express your answer in simplest radical form:
1.) 5x - 7x^2 = 3x + 4
2.) -x^2 + 4x = 13
Answers: 2.) https://web2.0calc.com/questions/solve-each-equation-and-express-your-answer-in-simplest_3
1.) https://web2.0calc.com/questions/solve-each-equation-and-express-your-answer-in-simplest_4
1. 5x - 7x^2 = 3x +4 add 7x^2 to both sides 0f the equation
5x = 7x^2 + 3x + 4 subtract 5x from both sides
0 = 7x^2 -5x +3x+4 simplify
0 = 7x^2 - 2x + 4 SInce the question states that it is 'radical form' you will need to use Quadratic Formula (rather than factoring) to find 'roots'
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
a = 7 b = -2 c = 4
[ 2 +- sqrt((-2)^2 - 4(7)(4) ] / [ 2(7) ] = 2 +- sqrt(-108) / 14 = 2+- 6i sqrt(3) / 14 = 1/7 +- 3/7 i sqrt(3)
Think you can do the second one now?
2. - x^2 +4x = 13
x^2 -4x +13 = 0 a = 1 b = -4 c = 13