Not sure how to do these.. Would be grateful if steps are shown and x values are in radians..
8 tan (x) + 11 = 19 subtract 11 from both sides
8 tan (x) = 8 divide both sides by 8
tan ( x) = 1
And this is true when x = pi/4 and x = 5pi/4 in the requested interval
sec^2 (x) = 2 tan^2 (x)
Note that tan^2(x) + 1 = sec^2 (x)....so we can write
tan^2(x) + 1 = 2tan^2(x) rearrange as
tan^2(x) = 1 subtract 1 from both sides
tan^2 (x) - 1 = 0 factor
(tan (x) + 1) ( tan (x) - 1) = 0
Set each factor to ) and solve
tan (x) + 1 = 0 tan (x) - 1 = 0
tan (x) = -1 tan (x) = 1
And this is true at And this is true at
3pi/4 ± n*pi pi/4 ± n*pi
Where n is an integer
sec^2(x) + sec^2(x) - 1 = 3 subtract 1 from both sides
2sec^2(x) = 2 divide both sides by 2
sec^2(x) = 1 subtract 1 from both sides
sec^2(x) - 1 = 0 factor
( sec (x) - 1) (sec (x) + 1 ) = 0
Set each factor to 0 and solve
sec(x) - 1 = 0 sec(x) + 1 = 0
sec(x) = 1 sec(x) = -1
And this is true at And this is true at
0 ± n*2pi pi ± n*2pi
Where n is an integer