+130458 I assume we have....
1 / [2n^2] + 5 / [2n] = n - 2 /[n^2] multiply through by 2n^2....this gives...
1 + 5n = 2n^3 - 4 rearrange
2n^3 - 5n - 5 = 0 this isn't factorable.....the only "real" solution occurs at about n = 1.946
See the graph here......https://www.desmos.com/calculator/q449wlwqlg
2[n3]−5n−5=0⇒{n=5×(√3×i2−12)(6×(5×√17(4×3(32))+54)(13))+(5×√17(4×3(32))+54)(13)×(−√3×i2−12)n=(5×√17(4×3(32))+54)(13)×(√3×i2−12)+5×(−√3×i2−12)(6×(5×√17(4×3(32))+54)(13))n=(5×√17(4×3(32))+54)(13)+5(6×(5×√17(4×3(32))+54)(13))}⇒{n=−0.9727551032709161−0.5820287560064501in=−0.9727551032709161+0.5820287560064501in=1.9455102065418322}
+130458 I assume we have....
1 / [2n^2] + 5 / [2n] = n - 2 /[n^2] multiply through by 2n^2....this gives...
1 + 5n = 2n^3 - 4 rearrange
2n^3 - 5n - 5 = 0 this isn't factorable.....the only "real" solution occurs at about n = 1.946
See the graph here......https://www.desmos.com/calculator/q449wlwqlg
2[n3]−5n−5=0⇒{n=5×(√3×i2−12)(6×(5×√17(4×3(32))+54)(13))+(5×√17(4×3(32))+54)(13)×(−√3×i2−12)n=(5×√17(4×3(32))+54)(13)×(√3×i2−12)+5×(−√3×i2−12)(6×(5×√17(4×3(32))+54)(13))n=(5×√17(4×3(32))+54)(13)+5(6×(5×√17(4×3(32))+54)(13))}⇒{n=−0.9727551032709161−0.5820287560064501in=−0.9727551032709161+0.5820287560064501in=1.9455102065418322}
