log2(4096)logx(37999)=−4
log2(4096)=12
12logx((37999))=−4
12=−(4×logx(37999))
−3=logx(37999)
x−3=37999
1x3=37999
999=37×x3
27=x3
3√27=x
x=3
See Anonymous's answer below.