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 Solve for x :    \(x = 7^{\log_{7} 2 + \log_{7} 3}\) 

 Jun 6, 2018
 #1
avatar+101371 
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x  = 7 ^ (log 7 2  + log 7 3)

 

x = 7^[ log 7  (2 * 3) ]  

 

x  = 7^ [ log7 6 ]   ......using the log property   a^[log a b]   = b  , we have 

 

x  = 6

 

 

cool cool cool

 Jun 6, 2018

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