Solve for x : \(x = 7^{\log_{7} 2 + \log_{7} 3}\)
x = 7 ^ (log 7 2 + log 7 3)
x = 7^[ log 7 (2 * 3) ]
x = 7^ [ log7 6 ] ......using the log property a^[log a b] = b , we have
x = 6