+0

# Solve for x.

0
179
3
+921

Solve for x.

√x+5= √x+ 1

no solution

4

−4

2

I think it would be 4? I am not sure.

Oct 24, 2018

#3
+2

Solve for x:
sqrt(x + 5) = sqrt(x) + 1

Raise both sides to the power of two:
x + 5 = (sqrt(x) + 1)^2

Subtract (sqrt(x) + 1)^2 from both sides:
5 - (sqrt(x) + 1)^2 + x = 0

5 - (sqrt(x) + 1)^2 + x = 4 - 2 sqrt(x):
4 - 2 sqrt(x) = 0

Subtract 4 from both sides:
-2 sqrt(x) = -4

Divide both sides by -2:
sqrt(x) = 2

Raise both sides to the power of two:
x = 4

Oct 24, 2018

#1
+101234
+1

As you have it written....no  solution

Think about this....whatever √ x  is on one side it is the same thing on the other side

But  adding 5 to this value on one side will always be  3 more than adding 2 to it on the other side

So.... the left side > right side for any  x value  ≥ 0

Oct 24, 2018
#2
+921
0

This is how it looks would it still be no soultion ? i am kinda confused.

the square root goes only goes across x+5 and the square root just goes on x for the second equation

jjennylove  Oct 24, 2018
edited by jjennylove  Oct 24, 2018
#3
+2

Solve for x:
sqrt(x + 5) = sqrt(x) + 1

Raise both sides to the power of two:
x + 5 = (sqrt(x) + 1)^2

Subtract (sqrt(x) + 1)^2 from both sides:
5 - (sqrt(x) + 1)^2 + x = 0

5 - (sqrt(x) + 1)^2 + x = 4 - 2 sqrt(x):
4 - 2 sqrt(x) = 0

Subtract 4 from both sides:
-2 sqrt(x) = -4

Divide both sides by -2:
sqrt(x) = 2

Raise both sides to the power of two:
x = 4

Guest Oct 24, 2018