Solve for x.
√x+5= √x+ 1
no solution
4
−4
2
I think it would be 4? I am not sure.
Solve for x:
sqrt(x + 5) = sqrt(x) + 1
Raise both sides to the power of two:
x + 5 = (sqrt(x) + 1)^2
Subtract (sqrt(x) + 1)^2 from both sides:
5 - (sqrt(x) + 1)^2 + x = 0
5 - (sqrt(x) + 1)^2 + x = 4 - 2 sqrt(x):
4 - 2 sqrt(x) = 0
Subtract 4 from both sides:
-2 sqrt(x) = -4
Divide both sides by -2:
sqrt(x) = 2
Raise both sides to the power of two:
x = 4
As you have it written....no solution
Think about this....whatever √ x is on one side it is the same thing on the other side
But adding 5 to this value on one side will always be 3 more than adding 2 to it on the other side
So.... the left side > right side for any x value ≥ 0
This is how it looks would it still be no soultion ? i am kinda confused.
the square root goes only goes across x+5 and the square root just goes on x for the second equation
Solve for x:
sqrt(x + 5) = sqrt(x) + 1
Raise both sides to the power of two:
x + 5 = (sqrt(x) + 1)^2
Subtract (sqrt(x) + 1)^2 from both sides:
5 - (sqrt(x) + 1)^2 + x = 0
5 - (sqrt(x) + 1)^2 + x = 4 - 2 sqrt(x):
4 - 2 sqrt(x) = 0
Subtract 4 from both sides:
-2 sqrt(x) = -4
Divide both sides by -2:
sqrt(x) = 2
Raise both sides to the power of two:
x = 4