+1124 Hi good people!!!....
The sum is:
\(x-3 \sqrt{x+2}=2\)
when we solve x, we get x=14 or x=-1
-1 is rendered na, but 14, not---why is this?
If I replace x with -1, we get
\(-1-3 \sqrt{-1+2}=2\)
which is \(-4 \sqrt{1}=2\)
which is \(-4=2\)...which of course is NOT..
But the same goes for the 14??
\(14-3 \sqrt{14+2}=2\)
which is \(11 \sqrt{16}=2\)
which is \(44=2\)
which also is NOT???
all and any answer is very appreciated!..thank you all kindly.
+37146 -1` - 3 sqrt(-1+2) = 2 ????? no it does not...it equals -4
the solutions you obtained are both incorrect...you made a mistake somewhere (we ALL do !)
......go back and solve it again to get different answers
+37146 Update : I looked at it a little closer:
x-2 = 3 (sqrt(x+2)) square both sides
x^2 - 4x + 4 = 9 (x+2)
x^2 -13x -14 = 0
Quadratic equation shows x = -1 and 14
14 - 3 sqrt (14+2) = 2
14 - 3 (sqrt16) = 2 ( look at your step where you get 11 sqrt (16) <---- this is where you made your error)
14 - 12 = 2 so 14 IS an answer only -1 is NOT.
+1124 aawww, you know what I did?????...I did not follow the order of operations when I checked the roots.....Thank you for your time, I do appreciate..
