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solve for y -5y+3(y+6)=32

 Jul 26, 2014

Best Answer 

 #1
avatar+4473 
+5

y -5y+3(y+6)=32

Our goal is to get one term with "y" on one side and a number on the other side:

First, distribute the 3 by multiplying it to both 'y' and '6': y - 5y + 3y + 18 = 32.

Second, combine like terms (the terms with "y") and subtract 18 from both sides to get a number on the right side: 

(1)y - 5y + 3y = -1y = -y

32 - 18 = 14

Therefore, we have -y = 14 --> divide both sides by "-1" to obtain y = -14.

Do a check to see if the equation makes sense.

y -5y+3(y+6)=32; plug in y = -14:

-14 - 5(-14) + 3(-14 + 6) = 32 --> 

-14 + 70 +3(-8) = 32 -->

56 - 24 = 32 -->

32 = 32 --> Yes.

 Jul 26, 2014
 #1
avatar+4473 
+5
Best Answer

y -5y+3(y+6)=32

Our goal is to get one term with "y" on one side and a number on the other side:

First, distribute the 3 by multiplying it to both 'y' and '6': y - 5y + 3y + 18 = 32.

Second, combine like terms (the terms with "y") and subtract 18 from both sides to get a number on the right side: 

(1)y - 5y + 3y = -1y = -y

32 - 18 = 14

Therefore, we have -y = 14 --> divide both sides by "-1" to obtain y = -14.

Do a check to see if the equation makes sense.

y -5y+3(y+6)=32; plug in y = -14:

-14 - 5(-14) + 3(-14 + 6) = 32 --> 

-14 + 70 +3(-8) = 32 -->

56 - 24 = 32 -->

32 = 32 --> Yes.

AzizHusain Jul 26, 2014

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