Solve g(x) = -10 and g(x) > f(x) for the given equations f(x)=x^2 and g(x)=1/(x^3) and what is the symmetry axis or point of axis for both graphs.
+1224 \(g(x) = \frac{1}{x^3} = -10\)
\(1 = -10x^3 \qquad \rightarrow \qquad -\frac{1}{10} = x^3 \qquad \rightarrow \qquad x = \boxed{-\frac{1}{\sqrt[3]{10}}}\)
\(g(x) > f(x) \qquad \rightarrow \qquad \frac{1}{x^3} > x^2\)
\(1 > x^5 \qquad \rightarrow \qquad \boxed{x \in (-\infty, 1)}\)
g(x) = 1/(x^3)
asymptote at y = 0 and x = 0
f(x) = x^2
axis of symmetry at x = 0
