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1) 3x^2 + 81=0

2) 6x^2 = -126

3) (1/4)x^2 + 12=0

 

Solve by using this symbol "±​".

 Aug 15, 2018
edited by Mathrules  Aug 15, 2018
edited by asinus  Aug 15, 2018
 #1
avatar+26396 
+2

1)

3x^2 + 81=0

 

3x2+81=0|:3x2+27=0|27x2=27x2=(1)93x=±(1)93x=±931|1=ix=±33i

 

laugh

 Aug 15, 2018
edited by heureka  Aug 15, 2018
 #2
avatar+26396 
+2

2)
6x^2 = -126

 

6x2=126|:6x2=21x2=(1)21x=±(1)21x=±211|1=ix=±21i

 

laugh

 Aug 15, 2018
edited by heureka  Aug 15, 2018
 #3
avatar+26396 
+2

3)
(1/4)x^2 + 12=0

 

(1/4)x2+12=0|4x2+48=0|48x2=48x2=(1)163x=±(1)163x=±1631|1=ix=±43i

 

laugh

 Aug 15, 2018

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