1) 3x^2 + 81=0
2) 6x^2 = -126
3) (1/4)x^2 + 12=0
Solve by using this symbol "±".
1)
3x^2 + 81=0
3x2+81=0|:3x2+27=0|−27x2=−27x2=(−1)⋅9⋅3x=±√(−1)⋅9⋅3x=±√9√3√−1|√−1=ix=±3√3⋅i
2)6x^2 = -126
6x2=−126|:6x2=−21x2=(−1)⋅21x=±√(−1)⋅21x=±√21√−1|√−1=ix=±√21⋅i
3)(1/4)x^2 + 12=0
(1/4)x2+12=0|⋅4x2+48=0|−48x2=−48x2=(−1)⋅16⋅3x=±√(−1)⋅16⋅3x=±√16√3√−1|√−1=ix=±4√3⋅i