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Find the probability of no more than 2 successes in 5 trials of a binomial experiment in which the probability of success in any one trial is 18%

 Mar 29, 2020
 #1
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Although I am not so great on these problems, I have found a very useful article that you can use to solve this problem.

 

Here is the link:

https://www.varsitytutors.com/hotmath/hotmath_help/topics/binomial-probability

 Mar 29, 2020
 #2
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This is a binomial probability problem.  The relevant formula is:  prob  =  nCr·pr·qn - r 

where:  n  =  total number of trials          n = 5

             r  =  number of successes         r = 0, 1, 2

             p  =  probability of success        p = 0.18

             q  =  probability of failure           q = (1.00 - 0.18)  =  0.82

 

For this problem, to find the total probability, we need to find the probability for 0 successes, then 1 success, and

finally 2 successes, and add them together.

 

Total probability  =  5C0·(0.18)0·(0.82)5  +  5C1·(0.18)1·(0.82)4  +  5C2·(0.18)2·(0.82)4 

 

Now, it's between you and your calculator!

 Mar 29, 2020

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