Find the probability of no more than 2 successes in 5 trials of a binomial experiment in which the probability of success in any one trial is 18%

Guest Mar 29, 2020

#1**+1 **

Although I am not so great on these problems, I have found a very useful article that you can use to solve this problem.

Here is the link:

https://www.varsitytutors.com/hotmath/hotmath_help/topics/binomial-probability

CalTheGreat Mar 29, 2020

#2**0 **

This is a binomial probability problem. The relevant formula is: prob = _{n}C_{r}·p^{r}·q^{n - r}

where: n = total number of trials n = 5

r = number of successes r = 0, 1, 2

p = probability of success p = 0.18

q = probability of failure q = (1.00 - 0.18) = 0.82

For this problem, to find the total probability, we need to find the probability for 0 successes, then 1 success, and

finally 2 successes, and add them together.

Total probability = _{5}C_{0}·(0.18)^{0}·(0.82)^{5} + _{5}C_{1}·(0.18)^{1}·(0.82)^{4} + _{5}C_{2}·(0.18)^{2}·(0.82)^{4}

Now, it's between you and your calculator!

geno3141 Mar 29, 2020