solve

hamza:

23q+3b=-9
21q-4b=3

One way is as follows:

Multiply the first equation through by 4 and the second equation through by 3 to get

92q + 12b = -36
63q - 12b = 9

Now add these two equations together to get

155q = -27

This allows you to find q. Then substitute the value you find back into one of the original equations and rearrange to find b.

Quote:

23q+3b=-9
21q-4b=3

probably the easiest way to go about this is using row reduction.

add 4 times the first equation to 3 times the second to get rid of the b variable

4(23q+3b=-9) +
3(21q-4b=3) =

92q+12b=-36 +
63q-12b=9
=
155q=-27

q = -27/155

from the second equation

21(-27/155)-4b=3

-567/155 - 4b = 3

4b = -567/155 - 3

b= (-567/155 - 3)/4 = -258/155

so (q,b) = (-27/155, -258/155)