b^2-6b+5=0
Using the quadratic formula, we get: −b±√b2−4ac2a⇔−(−6)±√(−6)24⋅1⋅52⋅1⇔6±√(−6)2−4⋅1⋅52⋅1⇔6±√162⋅1⇔6±42=5,1.
...or factoring (which you will eventually be able to do 'in your head')
(b-5)(b-1) = 0 so b-5 = 0 means b = 5 or b-1 = 0 means b = 1
Hello Guest!
b2−6b+5=0
p q
b=−p2±√(p2)2−qb=3±√9−5b=3±2
b1=5b2=1
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