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Solve for the variable x in terms of y and z, assuming y \neq \frac{1}{2}:
xy + x = \frac{3x + 2y + z + y + 2z}{3}

bingboy Feb 20, 2024

Best Answer

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$xy + x = \frac{3x + 2y + z + y + 2z}{3}$

$xy+x=\frac{3x+3y+3z}{3}$ .

$xy+x=x+y+z$

$xy=y+z$

$x=\frac{y+z}{y}$ . Can also be written as: $x=1+\frac{z}{y}$ .

hairyberry Feb 20, 2024

1⁺⁰ Answers

+410

+2

Best Answer

$xy + x = \frac{3x + 2y + z + y + 2z}{3}$

$xy+x=\frac{3x+3y+3z}{3}$ .

$xy+x=x+y+z$

$xy=y+z$

$x=\frac{y+z}{y}$ . Can also be written as: $x=1+\frac{z}{y}$ .

hairyberry Feb 20, 2024

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