#1**0 **

As you can see in the sqaure roots we can extract the x^2's, as \sqrt{x^2} = x, we can do the same with the 4 and our equation(s) become:

2x + x = 6 + 3x (1)

-2x + x = 6 + 3x (2)

2x - x = 6 + 3x (3)

-2x - x = 6 + 3x (4)

!! Notice the signs as (-2)^2 = (2)^2, and the prblem is asking us to find all values of x !!

Solving the equations we get that x=:

(1): x = no solution

(2): x = -3/2

(3): x = -3

(4): x = -1

So our answer is **-3, -1, and -3/2! **

Hope this helped!

Other user, if you see a mistake please reply with your answer! I make mistakes!!

svphxxo Jul 12, 2023

#2**0 **

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LouisBarger
Jul 12, 2023