+0  
 
0
81
2
avatar

ou have been offered a great job at a very successful board game company. Your first assignment is to create spinners for a game that will be released very soon.

 

The first spinner must have a probability of ⅕ for each of the following options:

Move right 

Move left

Move up

Move down

Lose a turn

 

The second spinner must have a probability of ⅙ for each of the numbers 1-6. 

 

What is the probability that a player will lose a turn?

 

What is the probability that a player will move right or up more than 3 spaces? 

 

Is a player more likely to move down or left less than 3 spaces or move up more than 1 space? 


 

 Jun 9, 2020
 #1
avatar+131 
+5

Probabiliy = Desired Outcomes/All possible outcomes

 

1. All possible outcomes = 5

 

   Desired Outcomes = 1

 

So, the probability of losing a turn on the first spinner is 1/5

 

2. There is a 2/5 chance that you will either get a "Move Up" or "Move Right".

 

We cube 2/5 b/c we can't have use any other moves.

 

2/5 x 2/5 x 2/5 = 8/125

 

You try three yourself wih the information I have given you

 Jun 9, 2020
 #2
avatar
0

I think you have to spin the 2nd spinner if you get all the options except lose a turn in the 1st spinner. 

If so, the probability of getting lose a turn would 1/25/ The probability for the 2nd part of the question would be 6/25. For the 3rd part of the question, it would be 5/25. 

Guest Jun 9, 2020

5 Online Users

avatar