I'm not sure how to approach this problem. So far I thought about multiplying the 2 by the other 2. Some assistance would be appreciated.

2(x)^3-2n 2(1/x)^2n = 4(1/x)^n+3

2(x)^{(3-2n) }* 2(x)^{-2n} = 4(x)^{-(n+3) } **multiply on the left side to make 4(x)^{m+n}

^{ }

4(x)^{(3-2n-2n) } = 4(x)^{-(n+3) }

3-4n = -n-3

-3n = -6

I think, you can see the whole picture now.