I'm not sure how to approach this problem. So far I thought about multiplying the 2 by the other 2. Some assistance would be appreciated.
2(x)^3-2n 2(1/x)^2n = 4(1/x)^n+3
2(x)(3-2n) * 2(x)-2n = 4(x)-(n+3) **multiply on the left side to make 4(x)m+n
4(x)(3-2n-2n) = 4(x)-(n+3)
3-4n = -n-3
-3n = -6
I think, you can see the whole picture now.
