How would you find all the solutions of x^5 - 3x^4 - 2x^3 - 4x^2 - 24x + 32
To find rational answers, factor the constant term (32) and divide each of these numbers by the factors of the coefficient of the iinitial term (1).
The factors of 32 are +1, -1, +2, -2, +4, -4, +8, -8. +16. -16. +32, and -32.
Try these, one at a time, until you find one that makes the expresssion zero.
If you try +1, the expression becomes zero; this tells you that one of the answers is +1, and one of the factors of the expression is (x - 1).
Now, there are a couple of things that you can do.
You can divide the original expression by (x - 1) to give you a smaller expression:
x4 - 2x3 -4x2 - 8x - 32
Again, factor the constant term (32) and divide each of these numbers by the facotrs of the coefficient of the initial term (1).
And again, these factor are +1, -1, +2, -2, +4, -4, +8, -8. +16. -16. +32, and -32.
Try these, one at a time, until you find one that makes the expression zero.
This will give you a second solution ... create the factor .... divide, and continue this process until you can no longer get another solution.
Solve for x:
x^5 - 3 x^4 - 2 x^3 - 4 x^2 - 24 x + 32 = 0
The left hand side factors into a product with four terms:
(x - 4) (x - 1) (x + 2) (x^2 + 4) = 0
Split into four equations:
x - 4 = 0 or x - 1 = 0 or x + 2 = 0 or x^2 + 4 = 0
Add 4 to both sides:
x = 4 or x - 1 = 0 or x + 2 = 0 or x^2 + 4 = 0
Add 1 to both sides:
x = 4 or x = 1 or x + 2 = 0 or x^2 + 4 = 0
Subtract 2 from both sides:
x = 4 or x = 1 or x = -2 or x^2 + 4 = 0
Subtract 4 from both sides:
x = 4 or x = 1 or x = -2 or x^2 = -4
Take the square root of both sides:
Answer: |x = 4 or x = 1 or x = -2 or x = 2 i or x = -2 i
How would you find all the solutions of x^5 - 3x^4 - 2x^3 - 4x^2 - 24x + 32
\( x^5 - 3x^4 - 2x^3 - 4x^2 - 24x + 32 \) is a term. There is no solution.
I guess you mean a function and you're looking for the zeros.
\(f(x)= x^5 - 3x^4 - 2x^3 - 4x^2 - 24x + 32 =0\)
Solution guess and simplify term several times by polynomial division.
\(x_1=-2\)
\(x_2=1\)
\(x_3=4\)
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