For each triangle, find all three side lengths to the nearest hundredth and all three angle measuers to the nearest degree.
Let's see...
We can use Pythagora's theorem:a^2+b^2=c^2.
1. side bc: let's move point b to 0,0. subtract the coordinates of point b to point c and you get that the coordinates of c is now 5,7. now, saying a=5 and b=7, we subsitute: 5^2+7^2=49+25=74. now as in the equation, we do sqrt(74), and done. same with others.
ans=8.6
side cd: since this is a right triangle, we just see what the difference between the 2 points are.
3,3 2,3
the difference is 5.
side db:-2,3 -2,-4
the difference is 7.
that is about all i can give you.I am having problems with this calculator on sine, cosine, and tangent so i cant give you angles.