We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

1. Given the functions f(x)=1/x−3 (to the side of the fraction) +1 and g(x)=1/x+4 (to the side of the fraction)+3 .

Which statement describes the transformation of the graph of function f onto the graph of function g?

Options:

The graph shifts 2 units right and 7 units down.

The graph shifts 7 units right and 2 units down.

The graph shifts 2 units left and 7 units up.

The graph shifts 7 units left and 2 units up.

2.

What are the coordinates of the hole in the graph of the function f(x) ?

f(x)=x^2+3x−28/x+7

_____, _______

Thanks again. Happy Valentnes day.

PhoenixForever Feb 14, 2019

#1**+2 **

First one

f(x) = 1 / (x - 3) + 1

g(x) = 1 / (x + 4) + 3

g(x) is translated 7 units to the left and 2 units up

Second one

(x^2 + 3x - 28) / ( x + 7) factor the numerator

[ ( x + 7) (x - 4) ] /( x + 7) cancel the ( x + 7)

x - 4

Since x = - 7 makes the denominator of the original fraction = 0.....the "hole" occurs at x = -7

To find the y coordinate of the "hole"...put -7 into x - 4 for x = - 7 - 4 = -11

So....the "hole" occurs at ( -7, -11)

CPhill Feb 14, 2019

#2**+1 **

Thank you so much for your help! As always, your explanations are always easier to understand. :)

PhoenixForever
Feb 14, 2019