+0  
 
0
843
2
avatar+11912 

You are told that i,331 is a perfect cube.Can you guess without factorisation what is its cube root ? Similarly , guess the cube roots of 4913, 12167,32768.

 

Pls can you just show and explain me how to do the first one and then i will try all others by myself!im really bad in  roots so pls make it easy!

 

 Aug 30, 2014

Best Answer 

 #1
avatar+118673 
+8

Mmm lets see.  I don't know if you have been given a technique Rosala.

$$\sqrt[3]{4913}$$

 

What digit cubed ends in 3 . 

1^3=1, 2^3=8, 3^3=27, 4^3=64, 5^3 no, 6^3 no, 7^3 yes no 8^3no 9^3=no

I know the number ends in 7 because 

7*7=47 9*7=63  No other's will end in 3

10^3=1000 too small

20^3=2^3*10^3=8000 too big

So the number has to be between 10 and 20 and end in 7

So the number has to be 17      

 Aug 30, 2014
 #1
avatar+118673 
+8
Best Answer

Mmm lets see.  I don't know if you have been given a technique Rosala.

$$\sqrt[3]{4913}$$

 

What digit cubed ends in 3 . 

1^3=1, 2^3=8, 3^3=27, 4^3=64, 5^3 no, 6^3 no, 7^3 yes no 8^3no 9^3=no

I know the number ends in 7 because 

7*7=47 9*7=63  No other's will end in 3

10^3=1000 too small

20^3=2^3*10^3=8000 too big

So the number has to be between 10 and 20 and end in 7

So the number has to be 17      

Melody Aug 30, 2014
 #2
avatar+11912 
0

Thank you very much MElody for that help!i just solved this question with a very easy technique!and this questions sounds super easy to me now which was first looking like a lost land to me!

 

Anyways thank u so much for the help!i'd give u soo many points for that!lol!

 Aug 30, 2014

0 Online Users