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If six people decide to come to a basketball game, but three of them are only 2/5 sure that they will stay for the entire time (the other three are sure they'll stay the whole time), what is the probability that at the end, at least 5 people stayed the entire time?

MathCuber  Aug 14, 2018
 #1
avatar+200 
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Sorry my solution is incorrect.

ColdplayMX  Aug 14, 2018
edited by ColdplayMX  Aug 14, 2018
 #2
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Thank you for trying. But I still need help

MathCuber  Aug 15, 2018
 #3
avatar+1203 
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Solution:

 

\( \text {Three of the six will remain at the game until its conclusion, this leaves three (3) }\\ \text {with a 40% probability of remaining at the game until its conclusion.}\\ \text {Find the probability that two (2) or more of these three (3) will remain. }\\ \text {To find this probability, calculate the Binomial CDF for } \large \rho \small (X \geq 2, 0.40)\\ \large \binom{3}{2}*0.4^2*0.6^1 + \binom{3}{3}*0.4^3 = 0.352\\ \;\\ \text {The probability is } 35.2\%\\ \)

 

 

 

GA

GingerAle  Aug 15, 2018

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