A 985kg car is driving in a circular track with a constant speed of 25.0 m/s. The circumference of the track is 2.75km. Find the centripetal acceleration of the car??????????

MicahSmith07 Oct 19, 2017

#1**+1 **

I'm not great at Physics but I believe the equation we need is :

a_{c } = v^2 / r

Where a_{c} is the centripetal acceleration, v is the velocity and r is the radius

Note..... convert 2.75 km to meters = 2750 m....this is the circumference....so to find the radius we have r = 2750 / [2 pi ] = [ 1375 / pi ] m

So we have

a_{c} = [25m/s]^2 / [1375 / pi ] m =

[ 625 m^2 / s^2] / [ 1375 / pi ] m =

[ (5/11 ) pi ] m / s^2 ≈

[ 0.4545 pi ] m / s^2 ≈

1.428 m / s^2

CPhill Oct 19, 2017