Sophie had 8200$ on her bankaccount.
After some time she had recived 164$ in interest rates. The rate was on 2,5%.
How many days did it take to get 164$?
Is this right?
8200*0,025 = 205
205/365 = 0,5616
164/0,5616 = 292 days
or is there any eaiser way to do it?
+129899 8200 + 164 = 8364
So.....assuming the interest rate is the annual rate, we have :
8364 = 8200(1 + .025)^t divide both sides by 8200
8364/8200 = (1.025)^t take the log of both sides
log [8364/8200] = log(1.025)^t and we can write
log [ 8364/8200] = t* log(1.025) divide both sides by log (1.025)
log[8364/8200] / log(1.025) = t = .8 of one year ≈ .8 x 365 ≈ 292 days
+10 2.5% = 2.5/100 = 5/200 = 1/40
8200*(1/40) = 8200/40 = 205
Less then one day?
You don't give enough information.
8,200 X [.025*d / 365] =164.00, solve for d.
Solve for d: 0.561644 d = 164. Divide both sides of 0.561644 d = 164. by 0.561644: (0.561644 d)/0.561644 = 164./0.561644 0.561644/0.561644 = 1: d = 164./0.561644 164./0.561644 = 292.: Answer: | | d = 292.
+18 Original post was posted non-logged-in so here we go with some more details:
Sophie had 8200$ on her bankaccount.
After some time she had recived 164$ in interest rates. The rate was on 2,5%.
How many days did it take to get 164$?
8200$*0,025 = 205$
(0,025 because of 2,5% interest rate = 0,025, and 205$ = Interest rates over a year)
205$/365 = 0,5616$
(365 because of 365 days a year)
164$/0,5616$ = 292 days
(164$ because of interest rates in $ and 0,5616$ because of the reciving per day)
+129899 8200 + 164 = 8364
So.....assuming the interest rate is the annual rate, we have :
8364 = 8200(1 + .025)^t divide both sides by 8200
8364/8200 = (1.025)^t take the log of both sides
log [8364/8200] = log(1.025)^t and we can write
log [ 8364/8200] = t* log(1.025) divide both sides by log (1.025)
log[8364/8200] / log(1.025) = t = .8 of one year ≈ .8 x 365 ≈ 292 days
