+0  
 
-1
615
3
avatar+54 

Heisenberg's Uncertainty Principle says that the product of the error in the measurement of a particle's momentum and the error in the measurement of a particle's position must be at least Planck's constant divided by . Suppose the error in the measurement of the momentum of a particle is halved. By how many percent does the minimum error in the measurement of its position increase?

 Jul 27, 2020
 #1
avatar+37159 
0

a particle's position must be at least Planck's constant divided by  ????   . Suppose the error in the measurement of the

 Jul 27, 2020
 #2
avatar+54 
-1

\(4\pi\)

 Jul 27, 2020
edited by Sub2JessieGamez  Jul 27, 2020
 #3
avatar+37159 
+1

Em * E= k/4pi

 

1/2 E* 2E= k/4pi

 

so halving the momentum error  DOUBLES the position error   ....   a 100% increase

 Jul 27, 2020

1 Online Users