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Heisenberg's Uncertainty Principle says that the product of the error in the measurement of a particle's momentum and the error in the measurement of a particle's position must be at least Planck's constant divided by . Suppose the error in the measurement of the momentum of a particle is halved. By how many percent does the minimum error in the measurement of its position increase?

 Jul 27, 2020
 #1
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a particle's position must be at least Planck's constant divided by  ????   . Suppose the error in the measurement of the

 Jul 27, 2020
 #2
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\(4\pi\)

 Jul 27, 2020
edited by Sub2JessieGamez  Jul 27, 2020
 #3
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Em * E= k/4pi

 

1/2 E* 2E= k/4pi

 

so halving the momentum error  DOUBLES the position error   ....   a 100% increase

 Jul 27, 2020

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