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# Sorry on the last one if it was me being lazy I am new to this site

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1) The graph of the parametric equations x= 2-3t, y= -1+5t is a line. What is the slope of this line?

2)Find the value of c such that the point (3,c) is on the graph of the parametric equations x = 6 + 2t, y = -2 +5t

3)At what point does the graph of the parametric equations x = 3-2t, y= -2 + 5t, intersect the graph of the parametric equations x = -1+3s, y=5-9s?

1) I first tried for the equation x=2-3t that if I added 8t to both sides of the equation. I would then get x+6 = 5t, so when I subsitute that in for y=-1+5t. so then I get y = 5+x. So the slope of the line should be one since slope in this equation should be the coeffecient of x then the slope should be 1? But it isn't

2) For 2 I graphed both the equations on desmos and I couldn't find any points for the x value of c. I don't know if i am graphing it correctly

3) Again, I struggle with graphing these equations so I tried graphing it on desmos once again and it didn't work out. I just need help with finding out how to correctly graph these equations

Nov 10, 2019

#1
+106981
+2

1) The graph of the parametric equations x= 2-3t, y= -1+5t is a line. What is the slope of this line?

What you tried

1) I first tried for the equation x=2-3t that if I added 8t to both sides of the equation. I would then get x+6 = 5t, so when I subsitute that in for y=-1+5t. so then I get y = 5+x. So the slope of the line should be one since slope in this equation should be the coeffecient of x then the slope should be 1? But it isn't

It has been a long time since I fiddled with parametric equations.

I'd probably multiply the first one by 5 and the second one by 3

then both equations could have 15t = something

Then it is super easy to eliminat the 15t but putting the other side of the equations equal to one another.

Try it for yourself.

Nov 10, 2019
#2
+106981
+1

And do not ask many questions at a time.

Learn from the answers that you get before you post more.

Nov 10, 2019
#3
+11092
+1

1) The graph of the parametric equations x= 2-3t, y= -1+5t is a line. What is the slope of this line?

2)Find the value of c such that the point (3,c) is on the graph of the parametric equations x = 6 + 2t, y = -2 +5t

3)At what point does the graph of the parametric equations x = 3-2t, y= -2 + 5t, intersect the graph of the parametric equations x = -1+3s, y=5-9s?

Nov 10, 2019