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A coin is tossed 12 times. How many different sequences of tosses could there have been, if the number of heads was at least 10

 

I've already tried to do (12 choose 10)+(12 choose 11)+1, but I'm not sure exactly what to do since it was wrong

 

Please help.

 Feb 5, 2023
 #1
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Since we're dealing with coin tosses, the number is actually 12*11 + 12 + 1 = 145.

 Feb 5, 2023
 #2
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A coin is tossed 12 times. How many different sequences of tosses could there have been, if the number of heads was at least 10

 

I've already tried to do (12 choose 10)+(12 choose 11)+1, but I'm not sure exactly what to do since it was wrong

 

Your solution is correct: [12 C 10] + [12 C 11] + [12 C 12] ==79 / 2^12 ==79 / 4,096

 Feb 5, 2023

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