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How many ways are there to put 5 balls in 3 boxes if the balls are not distinguishable but the boxes are?

 Feb 8, 2021
 #1
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k =  balls      n  = boxes

 

5 identical balls  into  3  distinguishable  boxes   (I'm assuming no restrictions.....a box may be  empty )

 

No.  of  ways =   C ( k + n - 1 ,  n -1)   =    C ( 5 + 3  -1  , 3 -1)  = C ( 7, 2)   =  21  ways

 

 

cool cool cool

 Feb 8, 2021

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