+0

# SOS!!!

0
230
7
+223

I cannot get the right answer for this problem for the life of me. If somebody would solve it I'd give them 5 stars.

THE PROBLEM:

(20+(1/4))x  +(5+(1/2)) = (7+(1/16))

(solve for x)

#1
+10

(20+(1/4))x + (5+(1/2)) = (7+(1/16))

(20(1/4))x = (7+(1/16)) - (5+(1/2))

x = ( (7+(1/16)) - (5+(1/2)) ) / (20+(1/4))

x = ((113/16) - (11/2)) / (81/4)

x = 25/324

Guest Mar 13, 2017
#1
+10

(20+(1/4))x + (5+(1/2)) = (7+(1/16))

(20(1/4))x = (7+(1/16)) - (5+(1/2))

x = ( (7+(1/16)) - (5+(1/2)) ) / (20+(1/4))

x = ((113/16) - (11/2)) / (81/4)

x = 25/324

Guest Mar 13, 2017
#6
+223
+5

This one seems to work! Thanks!

#5
+7153
+6

$$(20\frac{1}{4})x + 5\frac{1}{2} = 7\frac{1}{16} \\~\\ (\frac{81}{4})x + \frac{11}{2} = \frac{113}{16} \\~\\ (\frac{81}{4})x = \frac{113}{16} - \frac{11}{2} \\~\\ (\frac{81}{4})x = \frac{113}{16} - \frac{11(8)}{2(8)} \\~\\ (\frac{81}{4})x = \frac{113}{16} - \frac{88}{16} \\~\\ (\frac{81}{4})x = \frac{113-88}{16} \\~\\ (\frac{81}{4})x = \frac{25}{16} \\~\\ x = \frac{25}{16} / \frac{81}{4} \\~\\ x = \frac{25}{16} * \frac{4}{81} \\~\\ x = \frac{25*4}{16*81} \\~\\ x = \frac{100}{1296} = \frac{25}{324}$$

hectictar  Mar 13, 2017
#7
+223
+5

Since this one's laid out so nicely I'll give it 5 stars also! Thank you for your help, too!