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Sound intensities, I, are often compared with the threshold of human hearing, I_0, which is about 10^-12 watts per meter squared. The relative intensity, R, of a sound is given by the equation: R = 10log(I/I_0)

 

 

i. The intensity of a whisper is about 300 times as loud as the threshold of human hearing. Find the relative intensity, R, of a whisper in decibels.

 

 

ii.  Suppose a burglar alarm has a rating of 120 decibels. Compare this intensity to the threshold of human hearing.

 Mar 11, 2019
 #1
avatar+7477 
0

The intensity of whisper is 300 times of the threshold. That means \(I_{\text{whisper}} = 300I_0\).

\(R_{\text{whisper}} = 10\log\left(\dfrac{300I_0}{I_0}\right) = 10\log 300 \approx 24.77\;\text{dB}\)

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 Mar 12, 2019
 #2
avatar+7477 
0

\(120 = 10\log\left(\dfrac{I}{I_0}\right)\\ 120 = 10\log\left(\dfrac{I}{10^{-12}}\right)\\ 10^{12} = \dfrac{I}{10^{-12}}\\ I = 10^{24} \;\text{Wm}^{-2}\)

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 Mar 12, 2019
 #3
avatar+27664 
0

This is a repeat of the question at https://web2.0calc.com/questions/algebra-help_38#r1

 

(Max, you might want to check your answer to part ii).

 Mar 12, 2019

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