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What is the sound intensity of a jackhammer that is rated at 90 dB? 

 

I got 10^9. Am I correct? I used the formula: L=10log(I/Io) <--- Sound Intensity formula 

 Dec 22, 2017
edited by Julius  Dec 22, 2017
 #1
avatar+18331 
+1

90 = 10 log (I/(10^-12)

9=log (I/(10^-12)

I = .001  =1 x 10^-3  W/m^2

 Dec 22, 2017
 #2
avatar+18331 
+1

I realize this is the THIRD time you have posted the SAME question....PLEASE reply to the original thread with follow-up questions to avoid multiple people answering in multiple places....avoids confusion     THANX ! 

   ~EP

 Dec 22, 2017
 #3
avatar+956 
+1

I see :D Thank you so much! 

 

And sorry if I caused any confusion. 

 Dec 22, 2017

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