What is the sound intensity of a jackhammer that is rated at 90 dB?
I got 10^9. Am I correct? I used the formula: L=10log(I/Io) <--- Sound Intensity formula
90 = 10 log (I/(10^-12)
9=log (I/(10^-12)
I = .001 =1 x 10^-3 W/m^2
I realize this is the THIRD time you have posted the SAME question....PLEASE reply to the original thread with follow-up questions to avoid multiple people answering in multiple places....avoids confusion THANX !
~EP
I see :D Thank you so much!
And sorry if I caused any confusion.