sampson: What is the speed of a car that left skid marks of 405ft?
Hey sampson!
That depends on the braking acceleration.
In my country the required minimum is 7 m/s^2 (metric system I'm afraid).
The formula that I know is:
v^2 = 2 a s
where v is the initial speed, a is the braking acceleration, and s is the braking distance (skid marks).
Or perhaps you have another formula?
Assuming a "skid acceleration" of say 7 m/s^2 (or do you have another value?), can you calculate the speed?