a=sqrt(6+sqrt(11))-sqrt(6-sqrt(11))
how much is a^2
a=√6+√11−√6−√11
find a2
a2=√6+√112+√6−√112−2×√6+√11×√6−√11
a2=(6+√11)+(6−√11)−2×√((6+√11)×(6−√11))
a2=6+√11+6−√11−2×√(36−11)
a2=12−2×√25
a2=12−2×5
a2=2
and that means that a=±√2 COOL !!!
