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sqrt(a^2sqrt(a^4,5),7)/sqrt(a,5)

Guest Dec 14, 2014

Best Answer 

 #1
avatar+93317 
+5

$${\frac{{\sqrt[{{\mathtt{{\mathtt{7}}}}}]{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{{\mathtt{a}}}^{{\mathtt{4}}}}}}}}{{\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{\mathtt{a}}}}}}$$

 

$$\\=\frac{\sqrt[7]{a^2\times a^{4*(1/5)}}}{a^{1/5}}\\\\
=\frac{\sqrt[7]{a^2\times a^{0.8}}}{a^{0.2}}\\\\
=\frac{\sqrt[7]{a^{2.8}}}{a^{0.2}}\\\\
=\frac{(a^{2.8})^{1/7}}{a^{0.2}}\\\\
=\frac{a^{2.8/7}}{a^{0.2}}\\\\
=\frac{a^{0.4}}{a^{0.2}}\\\\
=a^{0.4-0.2}\\\\
=a^{0.2}\\\\
=a^{1/5}\\\\
=\sqrt[5]{a}$$

Melody  Dec 14, 2014
 #1
avatar+93317 
+5
Best Answer

$${\frac{{\sqrt[{{\mathtt{{\mathtt{7}}}}}]{{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{{\mathtt{a}}}^{{\mathtt{4}}}}}}}}{{\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{\mathtt{a}}}}}}$$

 

$$\\=\frac{\sqrt[7]{a^2\times a^{4*(1/5)}}}{a^{1/5}}\\\\
=\frac{\sqrt[7]{a^2\times a^{0.8}}}{a^{0.2}}\\\\
=\frac{\sqrt[7]{a^{2.8}}}{a^{0.2}}\\\\
=\frac{(a^{2.8})^{1/7}}{a^{0.2}}\\\\
=\frac{a^{2.8/7}}{a^{0.2}}\\\\
=\frac{a^{0.4}}{a^{0.2}}\\\\
=a^{0.4-0.2}\\\\
=a^{0.2}\\\\
=a^{1/5}\\\\
=\sqrt[5]{a}$$

Melody  Dec 14, 2014

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