+0  
 
0
268
1
avatar+598 

Square ABCD has its center at $(8,-8)$ and has an area of 4 square units. The top side of the square is horizontal. The square is then dilated with the dilation center at (0,0) and a scale factor of 2. What are the coordinates of the vertex of the image of square ABCD that is farthest from the origin? Give your answer as an ordered pair.

michaelcai  Oct 24, 2017
 #1
avatar+86931 
+1

The vertex  on the dilated image of ABCD  farthest from the origin is  (18, -18)

 

I believe this is the correct picture :

 

CPhill  Oct 24, 2017
edited by CPhill  Oct 24, 2017

12 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.