What is the sum of all possible values of k for which \(x^2 + kx - 9x + 25\) is the square of a binomial?
Can you please give me steps or answer if possible?
+36916 (k-9) = a+b and a*b = 25 factors of 25 : 5 5 25 1 -5 -5 -25 -1 (these are 'a' and 'b')
since we want a square of a binomial.....only the RED pairs above apply ....
Taking each one :
k-9 = 5+5
k = 19 binomial is (x+5)^2 = x^2 + 10x + 25
Can you do the other?
+36916 (k-9) = a+b and a*b = 25 factors of 25 : 5 5 25 1 -5 -5 -25 -1 (these are 'a' and 'b')
since we want a square of a binomial.....only the RED pairs above apply ....
Taking each one :
k-9 = 5+5
k = 19 binomial is (x+5)^2 = x^2 + 10x + 25
Can you do the other?
