To do this sum would I square root 80 then plus the 1 or is it the square root of 80+1?  Then do I do the same to the bottom and divide bottom into top?

Walthamx  Nov 5, 2017

The argument within the square root must be evaluated before taking the square root of something. Therefore, simplify the fraction first and then take the square root.


\(\sqrt{\frac{80+1}{68-4}}\) Simplify the numerator and denominator before proceeding.
\(\sqrt{\frac{81}{64}}\) A square root rule worth knowing is that the square root of a fraction is equivalent to the square root of the numerator divided by the square root of the denominator. In other words, \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\). It is like "distributing" the square root, if you want to think of it that way.
\(\sqrt{\frac{81}{64}}=\frac{\sqrt{81}}{\sqrt{64}}\) Now, simplify the numerator and the denominator.
\(\frac{\sqrt{81}}{\sqrt{64}}=\frac{9}{8}=1.125\) This is your simplified answer.
TheXSquaredFactor  Nov 5, 2017

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