+168 
To do this sum would I square root 80 then plus the 1 or is it the square root of 80+1? Then do I do the same to the bottom and divide bottom into top?
+2446 The argument within the square root must be evaluated before taking the square root of something. Therefore, simplify the fraction first and then take the square root.
| \(\sqrt{\frac{80+1}{68-4}}\) | Simplify the numerator and denominator before proceeding. |
| \(\sqrt{\frac{81}{64}}\) | A square root rule worth knowing is that the square root of a fraction is equivalent to the square root of the numerator divided by the square root of the denominator. In other words, \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\). It is like "distributing" the square root, if you want to think of it that way. |
| \(\sqrt{\frac{81}{64}}=\frac{\sqrt{81}}{\sqrt{64}}\) | Now, simplify the numerator and the denominator. |
| \(\frac{\sqrt{81}}{\sqrt{64}}=\frac{9}{8}=1.125\) | This is your simplified answer. |
