+0  
 
0
225
1
avatar+164 

 

To do this sum would I square root 80 then plus the 1 or is it the square root of 80+1?  Then do I do the same to the bottom and divide bottom into top?

Walthamx  Nov 5, 2017
 #1
avatar+2143 
+1

The argument within the square root must be evaluated before taking the square root of something. Therefore, simplify the fraction first and then take the square root.

 

\(\sqrt{\frac{80+1}{68-4}}\) Simplify the numerator and denominator before proceeding.
\(\sqrt{\frac{81}{64}}\) A square root rule worth knowing is that the square root of a fraction is equivalent to the square root of the numerator divided by the square root of the denominator. In other words, \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\). It is like "distributing" the square root, if you want to think of it that way.
\(\sqrt{\frac{81}{64}}=\frac{\sqrt{81}}{\sqrt{64}}\) Now, simplify the numerator and the denominator.
\(\frac{\sqrt{81}}{\sqrt{64}}=\frac{9}{8}=1.125\) This is your simplified answer.
   
TheXSquaredFactor  Nov 5, 2017

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