To do this sum would I square root 80 then plus the 1 or is it the square root of 80+1? Then do I do the same to the bottom and divide bottom into top?

Walthamx
Nov 5, 2017

#1**+1 **

The argument within the square root must be evaluated before taking the square root of something. Therefore, simplify the fraction first and then take the square root.

\(\sqrt{\frac{80+1}{68-4}}\) | Simplify the numerator and denominator before proceeding. |

\(\sqrt{\frac{81}{64}}\) | A square root rule worth knowing is that the square root of a fraction is equivalent to the square root of the numerator divided by the square root of the denominator. In other words, \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\). It is like "distributing" the square root, if you want to think of it that way. |

\(\sqrt{\frac{81}{64}}=\frac{\sqrt{81}}{\sqrt{64}}\) | Now, simplify the numerator and the denominator. |

\(\frac{\sqrt{81}}{\sqrt{64}}=\frac{9}{8}=1.125\) | This is your simplified answer. |

TheXSquaredFactor
Nov 5, 2017