+0

# Square Roots

0
250
1
+164

To do this sum would I square root 80 then plus the 1 or is it the square root of 80+1?  Then do I do the same to the bottom and divide bottom into top?

Walthamx  Nov 5, 2017
#1
+2248
+1

The argument within the square root must be evaluated before taking the square root of something. Therefore, simplify the fraction first and then take the square root.

 $$\sqrt{\frac{80+1}{68-4}}$$ Simplify the numerator and denominator before proceeding. $$\sqrt{\frac{81}{64}}$$ A square root rule worth knowing is that the square root of a fraction is equivalent to the square root of the numerator divided by the square root of the denominator. In other words, $$\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$$. It is like "distributing" the square root, if you want to think of it that way. $$\sqrt{\frac{81}{64}}=\frac{\sqrt{81}}{\sqrt{64}}$$ Now, simplify the numerator and the denominator. $$\frac{\sqrt{81}}{\sqrt{64}}=\frac{9}{8}=1.125$$ This is your simplified answer.
TheXSquaredFactor  Nov 5, 2017