squeeze theorem

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use the squeeze theorem to evaluate the following limits: an=sin(1/n) / n. an=cos(1/n)-1 / 2^n

medlockb1234 Oct 8, 2017

edited by medlockb1234 Oct 9, 2017

Alan · Answer 1 · 2017-10-08T07:37:46

"use the squeeze theorem to evaluate the following limits: an=sin(1/n) over n. an=cos(1/n)-1 / 2^n"

a_n = sin(1/n) Try squeezing this between 1/n and 1/n² (should get 0)

a_n = cos(1/n) - 1/2ⁿ Try squeezing this between 1 - 1/n and 1 - 1/2ⁿ (should get 1)

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