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The mean of six numbers is 14. If one of the six numbers is removed, the mean becomes $$10$$. What is the value of the number removed?

May 14, 2022

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Let a, b, c, d, e, x be the 6 numbers, with x being the number that is removed.

$$\begin{cases}\dfrac{a + b + c + d + e + x}6 = 14\\\dfrac{a + b +c + d + e}5 = 10\end{cases}$$

That means a + b + c + d + e = 50. Substitute that into the first equation to get $$\dfrac{50 + x}6 = 14$$.

Can you work out the value of x from here? That is the number that was removed.

May 14, 2022
edited by MaxWong  May 14, 2022