Steve had 38 coins.They were twenty-cent and ten-cent coins.Their total value was $5.30.How many twenty-cent coins were there?

Guest Mar 18, 2015

#1**+5 **

Call the number of 20 cent coins "x"

Let the number of 10 cent coins be 38 - x

So, the number of coins times their value each gives us the total value....so we have

20x + 10(38 - x) = 530 simplify

20x + 380 - 10x = 530

10x + 380 = 530 subtract 380 from each side

10x = 150 divide both sides by 10

x = 15 ....and that's the number of 20 cent coins

CPhill
Mar 18, 2015

#1**+5 **

Best Answer

Call the number of 20 cent coins "x"

Let the number of 10 cent coins be 38 - x

So, the number of coins times their value each gives us the total value....so we have

20x + 10(38 - x) = 530 simplify

20x + 380 - 10x = 530

10x + 380 = 530 subtract 380 from each side

10x = 150 divide both sides by 10

x = 15 ....and that's the number of 20 cent coins

CPhill
Mar 18, 2015