Steve had 38 coins.They were twenty-cent and ten-cent coins.Their total value was $5.30.How many twenty-cent coins were there?
Call the number of 20 cent coins "x"
Let the number of 10 cent coins be 38 - x
So, the number of coins times their value each gives us the total value....so we have
20x + 10(38 - x) = 530 simplify
20x + 380 - 10x = 530
10x + 380 = 530 subtract 380 from each side
10x = 150 divide both sides by 10
x = 15 ....and that's the number of 20 cent coins
Call the number of 20 cent coins "x"
Let the number of 10 cent coins be 38 - x
So, the number of coins times their value each gives us the total value....so we have
20x + 10(38 - x) = 530 simplify
20x + 380 - 10x = 530
10x + 380 = 530 subtract 380 from each side
10x = 150 divide both sides by 10
x = 15 ....and that's the number of 20 cent coins