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1. How many moles of ammonia are produced when 15 liters of hydrogen are used in the below reaction at 12 atm and 300K?

N2 + 3H2 → 2NH3

 

2. How many liters of nitrogen are needed to produce 20 moles of ammonia (NH3) at 273K and 5 atm in the below reaction?

N2 + 3H2 → 2NH3

 

Please help. I'm sorry but this confuses me a lot! Thank you.

 Dec 4, 2018
 #1
avatar+18293 
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1

For every THREE moles of Hydrogen , TWO moles of ammonia are produced.

How many moles of Hydrogen are there?

PV=nRT  

  P ressure  V olume  n umber of moles   R=gas constant 0.082057 L atm mol-1K-1     T emp in K

12(15)= n (.082057)(300)        n = 7.312 moles

7.312/3  * 2 = 4.875 moles of ammonia produced

 Dec 4, 2018
 #2
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How did you get 7.312 moles? And the divide by 3 and multiply by 2? Sorry but I'm just confused about this. :(

Guest Dec 4, 2018
 #3
avatar+18293 
+1

I solved the PV=nRT equation to find n = 7.132 moles of H2

      3 moles of H2  produce   2 Moles of ammonia (according to the equation)

    

7.132/3 * 2 = 4.875 moles

ElectricPavlov  Dec 4, 2018
 #4
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Oh okay!! My apologies. Now I understand! Thank you so much.

Guest Dec 4, 2018
edited by Guest  Dec 4, 2018
 #5
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Sorry for bothering again! Do I use the same formula for the second question? I tried to but I got 302.18 and that is not correct. Thank you!

 Dec 4, 2018
 #6
avatar+18293 
+1

How many moles of ammonia are there?    20

 

2 moles of ammonia come from ONE mole of N2       How many moles of N2 is that?   What did you get?

 

 

THEN use    PV = n RT to find   V for the nitrogen....  Let me know waht you find....G'Luck !

ElectricPavlov  Dec 4, 2018
 #7
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I really hope this is right. I worked it out and got 44.8266 rounded to 44.83. Did I finally get the answer? I am so very sorry for bothering you!

Guest Dec 4, 2018
 #8
avatar+18293 
+1

Heck yah !    ( but I got 44.803)

ElectricPavlov  Dec 4, 2018
edited by ElectricPavlov  Dec 4, 2018

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