1. How many moles of ammonia are produced when 15 liters of hydrogen are used in the below reaction at 12 atm and 300K?
N2 + 3H2 → 2NH3
2. How many liters of nitrogen are needed to produce 20 moles of ammonia (NH3) at 273K and 5 atm in the below reaction?
N2 + 3H2 → 2NH3
Please help. I'm sorry but this confuses me a lot! Thank you.
+36916
1
For every THREE moles of Hydrogen , TWO moles of ammonia are produced.
How many moles of Hydrogen are there?
PV=nRT
P ressure V olume n umber of moles R=gas constant 0.082057 L atm mol-1K-1 T emp in K
12(15)= n (.082057)(300) n = 7.312 moles
7.312/3 * 2 = 4.875 moles of ammonia produced
How did you get 7.312 moles? And the divide by 3 and multiply by 2? Sorry but I'm just confused about this. :(
+36916 I solved the PV=nRT equation to find n = 7.132 moles of H2
3 moles of H2 produce 2 Moles of ammonia (according to the equation)
7.132/3 * 2 = 4.875 moles
Sorry for bothering again! Do I use the same formula for the second question? I tried to but I got 302.18 and that is not correct. Thank you!
+36916 How many moles of ammonia are there? 20
2 moles of ammonia come from ONE mole of N2 How many moles of N2 is that? What did you get?
THEN use PV = n RT to find V for the nitrogen.... Let me know waht you find....G'Luck !
I really hope this is right. I worked it out and got 44.8266 rounded to 44.83. Did I finally get the answer? I am so very sorry for bothering you!
