We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

1. How many moles of ammonia are produced when 15 liters of hydrogen are used in the below reaction at 12 atm and 300K?

N2 + 3H2 → 2NH3

2. How many liters of nitrogen are needed to produce 20 moles of ammonia (NH3) at 273K and 5 atm in the below reaction?

N2 + 3H2 → 2NH3

Please help. I'm sorry but this confuses me a lot! Thank you.

Guest Dec 4, 2018

#1**+1 **

1

For every THREE moles of Hydrogen , TWO moles of ammonia are produced.

How many moles of Hydrogen are there?

PV=nRT

P ressure V olume n umber of moles R=gas constant 0.082057 L atm mol-1K-1 T emp in K

12(15)= n (.082057)(300) n = 7.312 moles

7.312/3 * 2 = 4.875 moles of ammonia produced

ElectricPavlov Dec 4, 2018

#2**0 **

How did you get 7.312 moles? And the divide by 3 and multiply by 2? Sorry but I'm just confused about this. :(

Guest Dec 4, 2018

#3**+1 **

I solved the PV=nRT equation to find n = 7.132 moles of H2

3 moles of H2 produce 2 Moles of ammonia (according to the equation)

7.132/3 * 2 = 4.875 moles

ElectricPavlov
Dec 4, 2018

#5**0 **

Sorry for bothering again! Do I use the same formula for the second question? I tried to but I got 302.18 and that is not correct. Thank you!

Guest Dec 4, 2018

#6**+1 **

How many moles of ammonia are there? 20

2 moles of ammonia come from ONE mole of N2 How many moles of N2 is that? What did you get?

THEN use PV = n RT to find V for the nitrogen.... Let me know waht you find....G'Luck !

ElectricPavlov
Dec 4, 2018

#7**0 **

I really hope this is right. I worked it out and got 44.8266 rounded to 44.83. Did I finally get the answer? I am so very sorry for bothering you!

Guest Dec 4, 2018